Comments on: Calculating distances from latitude and longitude (PHP) http://sniptools.com/vault/calculating-distances-from-latitude-and-longitude-php Design & Technology Observations Sun, 18 Jul 2010 17:26:05 +0000 hourly 1 http://wordpress.org/?v=3.0 By: nik http://sniptools.com/vault/calculating-distances-from-latitude-and-longitude-php/comment-page-1#comment-788 nik Thu, 29 Sep 2005 07:40:14 +0000 http://sniptools.com/cms/?p=23#comment-788 postcode data and sql file at the attached url <a href="http://www.easypeasy.com/guides/article.php?article=64" rel="nofollow">http://www.easypeasy.com/guides/article.php?article=64</a> postcode data and sql file at the attached url

http://www.easypeasy.com/guides/article.php?article=64

]]> By: Mark Waterhouse http://sniptools.com/vault/calculating-distances-from-latitude-and-longitude-php/comment-page-1#comment-787 Mark Waterhouse Sun, 14 Aug 2005 03:29:27 +0000 http://sniptools.com/cms/?p=23#comment-787 Hi Does anyone have a copy of the postcode sql database? Its no longer available at the URL above. Thanks Mark Hi
Does anyone have a copy of the postcode sql database? Its no longer available at the URL above.

Thanks
Mark

]]> By: Dan Karran http://sniptools.com/vault/calculating-distances-from-latitude-and-longitude-php/comment-page-1#comment-786 Dan Karran Tue, 05 Jul 2005 13:50:12 +0000 http://sniptools.com/cms/?p=23#comment-786 Thanks. I found your page via Google and implemented the code in SQL (before realising someone else had done the work for me in your comments). I'm using it to calculate the distance between places I've taken photographs, and displaying the distances alongside a map using the new Google Maps API interface. <a href="http://www.dankarran.com/photography/map/?town=castletown" rel="nofollow">http://www.dankarran.com/photography/map/?town=castletown</a> Thanks. I found your page via Google and implemented the code in SQL (before realising someone else had done the work for me in your comments). I’m using it to calculate the distance between places I’ve taken photographs, and displaying the distances alongside a map using the new Google Maps API interface.

http://www.dankarran.com/photography/map/?town=castletown

]]> By: Tony Fox http://sniptools.com/vault/calculating-distances-from-latitude-and-longitude-php/comment-page-1#comment-785 Tony Fox Thu, 20 Jan 2005 02:57:55 +0000 http://sniptools.com/cms/?p=23#comment-785 The end of the script will not show because of the less than symbol add at the end "less than" 120) The end of the script will not show because of the less than symbol

add at the end “less than” 120)

]]> By: Tony Fox http://sniptools.com/vault/calculating-distances-from-latitude-and-longitude-php/comment-page-1#comment-784 Tony Fox Thu, 20 Jan 2005 01:26:36 +0000 http://sniptools.com/cms/?p=23#comment-784 Looks like the end of the script has been missed off. Try This:- SELECT a.Town,a.Postcode,b.lat_dec AS lat1,b.long_dec AS long1,c.lat_dec AS lat2,c.long_dec AS long2,round(degrees(acos(sin(radians(b.lat_dec))* sin(radians(c.lat_dec))+cos(radians(b.lat_dec))* cos(radians(c.lat_dec))*cos(radians(b.long_dec - c.long_dec))))*69, 2) AS distance FROM postcode_names a,postcode_data b,postcode_data c WHERE c.Postcode = 'NR32' AND a.Postcode = b.Postcode AND round(degrees(acos(sin(radians(b.lat_dec)) * sin(radians(c.lat_dec)) + cos(radians(b.lat_dec)) * cos(radians(c.lat_dec)) * cos(radians(b.long_dec - c.long_dec))))*69, 2) HAVING (distance Looks like the end of the script has been missed off. Try This:-

SELECT a.Town,a.Postcode,b.lat_dec AS lat1,b.long_dec AS long1,c.lat_dec AS lat2,c.long_dec AS long2,round(degrees(acos(sin(radians(b.lat_dec))* sin(radians(c.lat_dec))+cos(radians(b.lat_dec))* cos(radians(c.lat_dec))*cos(radians(b.long_dec – c.long_dec))))*69, 2) AS distance FROM postcode_names a,postcode_data b,postcode_data c WHERE c.Postcode = ‘NR32′ AND a.Postcode = b.Postcode AND round(degrees(acos(sin(radians(b.lat_dec)) * sin(radians(c.lat_dec)) + cos(radians(b.lat_dec)) * cos(radians(c.lat_dec)) * cos(radians(b.long_dec – c.long_dec))))*69, 2) HAVING (distance

]]> By: win http://sniptools.com/vault/calculating-distances-from-latitude-and-longitude-php/comment-page-1#comment-783 win Mon, 05 Jul 2004 18:57:37 +0000 http://sniptools.com/cms/?p=23#comment-783 How do you modify above script, if I want to display distance from 1 city to another. Not all. Having clause is missing from previous post. I'm having same thing happening. Shows all results, and if I use limit 1 it shows first record info. How do you modify above script, if I want to display distance from 1 city to another. Not all.

Having clause is missing from previous post.
I’m having same thing happening. Shows all results, and if I use limit 1 it shows first record info.

]]> By: Stew http://sniptools.com/vault/calculating-distances-from-latitude-and-longitude-php/comment-page-1#comment-782 Stew Wed, 21 Apr 2004 01:24:11 +0000 http://sniptools.com/cms/?p=23#comment-782 Thats very nice but when I ran the query I got every postcode returned. I found adding a 'HAVING' clause to the query did the trick - viz... SELECT a.Town, a.Postcode, b.lat_dec AS lat1, b.long_dec AS long1, c.lat_dec AS lat2, c.long_dec AS long2, round(degrees(acos(sin(radians(b.lat_dec)) * sin(radians(c.lat_dec)) + cos(radians(b.lat_dec)) * cos(radians(c.lat_dec)) * cos(radians(b.long_dec - c.long_dec))))*69, 2) AS distance FROM postcode_names a, postcode_data b, postcode_data c WHERE c.Postcode = 'NR32' AND a.Postcode = b.Postcode AND round(degrees(acos(sin(radians(b.lat_dec)) * sin(radians(c.lat_dec)) + cos(radians(b.lat_dec)) * cos(radians(c.lat_dec)) * cos(radians(b.long_dec - c.long_dec))))*69, 2) HAVING (distance Thats very nice but when I ran the query I got every postcode returned.

I found adding a ‘HAVING’ clause to the query did the trick – viz…

SELECT
a.Town,
a.Postcode,
b.lat_dec AS lat1, b.long_dec AS long1,
c.lat_dec AS lat2, c.long_dec AS long2,
round(degrees(acos(sin(radians(b.lat_dec))
* sin(radians(c.lat_dec))
+ cos(radians(b.lat_dec))
* cos(radians(c.lat_dec))
* cos(radians(b.long_dec – c.long_dec))))*69, 2) AS distance
FROM
postcode_names a, postcode_data b, postcode_data c
WHERE
c.Postcode = ‘NR32′
AND
a.Postcode = b.Postcode
AND
round(degrees(acos(sin(radians(b.lat_dec))
* sin(radians(c.lat_dec))
+ cos(radians(b.lat_dec))
* cos(radians(c.lat_dec))
* cos(radians(b.long_dec – c.long_dec))))*69, 2)
HAVING (distance

]]> By: wyldie http://sniptools.com/vault/calculating-distances-from-latitude-and-longitude-php/comment-page-1#comment-781 wyldie Mon, 12 Apr 2004 13:25:25 +0000 http://sniptools.com/cms/?p=23#comment-781 To pull distances from one UK postcode to another use the following SQL dump:- <a href="http://www.good-stuff.co.uk/useful/pcodedb.sql.gz" rel="nofollow">http://www.good-stuff.co.uk/useful/pcodedb.sql.gz</a> Now, presuming you're using MySQL, use the following converted code to have MySQL do all the math on your behalf. SELECT a.Town, a.Postcode, b.lat_dec AS lat1, b.long_dec AS long1, c.lat_dec AS lat2, c.long_dec AS long2, round(degrees(acos(sin(radians(b.lat_dec)) * sin(radians(c.lat_dec)) + cos(radians(b.lat_dec)) * cos(radians(c.lat_dec)) * cos(radians(b.long_dec - c.long_dec))))*69, 2) AS distance FROM postcode_names a, postcode_data b, postcode_data c WHERE c.Postcode = 'NR32' AND a.Postcode = b.Postcode AND round(degrees(acos(sin(radians(b.lat_dec)) * sin(radians(c.lat_dec)) + cos(radians(b.lat_dec)) * cos(radians(c.lat_dec)) * cos(radians(b.long_dec - c.long_dec))))*69, 2) To pull distances from one UK postcode to another use the following SQL dump:-
http://www.good-stuff.co.uk/useful/pcodedb.sql.gz

Now, presuming you’re using MySQL, use the following converted code to have MySQL do all the math on your behalf.

SELECT
a.Town,
a.Postcode,
b.lat_dec AS lat1, b.long_dec AS long1,
c.lat_dec AS lat2, c.long_dec AS long2,
round(degrees(acos(sin(radians(b.lat_dec))
* sin(radians(c.lat_dec))
+ cos(radians(b.lat_dec))
* cos(radians(c.lat_dec))
* cos(radians(b.long_dec – c.long_dec))))*69, 2) AS distance
FROM
postcode_names a, postcode_data b, postcode_data c
WHERE
c.Postcode = ‘NR32′
AND
a.Postcode = b.Postcode
AND
round(degrees(acos(sin(radians(b.lat_dec))
* sin(radians(c.lat_dec))
+ cos(radians(b.lat_dec))
* cos(radians(c.lat_dec))
* cos(radians(b.long_dec – c.long_dec))))*69, 2)

]]> By: sniptools http://sniptools.com/vault/calculating-distances-from-latitude-and-longitude-php/comment-page-1#comment-780 sniptools Wed, 24 Mar 2004 07:03:45 +0000 http://sniptools.com/cms/?p=23#comment-780 Hi William, Pls send me your code through email. When PHP throws a last line error, it is usually because a semicolon is missing from somewhere in your code, or perhaps a closing bracket (the "}" character i.e.) for some loop in your code etc. HTH, Shanx Hi William,

Pls send me your code through email. When PHP throws a last line error, it is usually because a semicolon is missing from somewhere in your code, or perhaps a closing bracket (the “}” character i.e.) for some loop in your code etc.

HTH,
Shanx

]]> By: william http://sniptools.com/vault/calculating-distances-from-latitude-and-longitude-php/comment-page-1#comment-779 william Tue, 23 Mar 2004 13:34:49 +0000 http://sniptools.com/cms/?p=23#comment-779 thank you kindly for the code! i'm having a hell of a time making it work though. do you have the full page-code (php included) posted? i used the php from the text field, but somewhere between the variables being sent, and the calculation i get a "parse error" on the last line, which can't be accurate since the last line is . thank you, -Confused thank you kindly for the code! i’m having a hell of a time making it work though. do you have the full page-code (php included) posted? i used the php from the text field, but somewhere between the variables being sent, and the calculation i get a “parse error” on the last line, which can’t be accurate since the last line is .

thank you,
-Confused

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